【 tulaoshi.com - 编程语言 】
一位网友正在学校做课程设计题目,要求在一个文件中找到给定单词出现的位置并统计出现次数。这是一个比较简单的文本处理问题， 于是， 我给他用 python 写了一个，并打赌在5分钟内用不到30行程序解决问题。 下面是程序： if __name__=='__main__':
file_name = raw_input('Input the file you want to find in:')
try:
in_file = open(file_name,'r')
lines = in_file.readlines()
tag_tok = ''
while tag_tok.upper() != 'Q':
tag_tok = raw_input('Input the Word you want to find(Q for quit):')
if tag_tok.upper() != 'Q':
count = 0
line_no = 0
for line in lines:
line_no = line_no + 1
inline_cnt = line.count(tag_tok)
count = count + inline_cnt
if inline_cnt 0:
print 'Find %s %d time(s) in line :%d'%(tag_tok,inline_cnt,line_no)
print line
print '---------------------------------'
print 'Total fount %s %d time(s)'%(tag_tok, count)
except:
print "Can't open file %s"%(file_name)但是，这个网友还不满足非要一个 C++的程序，理由是他们老师不会python ， 正好我也想试试用C++解决和python做下对比：#include fstream
#include iostream
#include string
#include vector
#include algorithmusing namespace std;int BruteFind(const char *x, int m, const char *y, int n ,vectorint& colpos) {
int i, j, cnt=0;
/* Searching */
for (j = 0; j = n - m; ++j) {
for (i = 0; i m && x == y[i + j]; ++i);
if (i = m){
colpos[cnt++] = j;
if(cnt == colpos.size())
colpos.resize(cnt * 2);
}
}
return cnt;
}int count_string(string source, string tag, vectorint& colpos){
int find_cnt = 0;
find_cnt = BruteFind(tag.c_str(), tag.size(), source.c_str(),source.size(),colpos); return find_cnt;
}int main(){
string file_name, line;
vectorstring lines;
lines.resize(10);
cout "Input the file name:";
cin file_name;
ifstream in_file;
try{
in_file.open(file_name.c_str());
if(!in_file)
throw(file_name);
}
catch(string file_name){
cout "Fatal error: File not found."endl;
exit(1);
}int line_count = 0;
do{
getline(in_file, lines[line_count]);
line_count ++;
if(line_count == lines.size()){
lines.resize(line_count * 2);
}
}while(in_file.eof()==0);
string tag_tok;
vectorint colpos;
colpos.resize(10);
do{
cout "Input the word you want to find(Q for quit):";
cin tag_tok;
if(tag_tok == "Q"){
break;
}
int count = 0, line_no = 0 , inline_count;
for(line_no = 0 ;line_no line_count ; line_no++){
inline_count = count_string(lines[line_no], tag_tok, colpos);
count += inline_count;
if(inline_count 0){
cout "Find " tag_tok " " inline_count " time(s) in line " line_no ;
cout " , column pos is ( ";
for(int i = 0 ;i inline_count ;i++){
cout colpos ' ';
}
cout " )" endl;
cout lines[line_no] endl;
}
}
cout "--------------------------------" endl;
cout "Total fount " tag_tok " " count " time(s)" endl;
}while(tag_tok != "Q");
in_file.close();
return 0;
}
这个程序用了30分钟。从程序长度和编程时间上，粗略对比下：Python 5 分钟 22行C++ 30 分钟 60多行从这个简单的例子中可以大体看到 脚本语言与C++语言中在开发时的差异了。
