java 字符串词频统计实例代码

【 tulaoshi.com - 编程语言 】

代码如下：

package com.gpdi.action;

import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

public class WordsStatistics {

    class Obj {
        int count ;
        Obj(int count){
            this.count = count;
        }
    }

    public ListWordCount statistics(String word) {
        ListWordCount rs = new ArrayListWordCount();
        Map String,Obj map = new HashMapString,Obj();

        if(word == null ) {
            return null;
        }
        word = word.toLowerCase();
        word = word.replaceAll("'s", "");
        word = word.replaceAll(",", "");
        word = word.replaceAll("-", "");
        word = word.replaceAll(".", "");
        word = word.replaceAll("'", "");
        word = word.replaceAll(":", "");
        word = word.replaceAll("!", "");
        word = word.replaceAll("n", "");

        String [] wordArray = word.split(" ");
        for(String simpleWord : wordArray) {
            simpleWord = simpleWord.trim(); 
            if (simpleWord != null && !simpleWord.equalsIgnoreCase("")) {
                Obj cnt = map.get(simpleWord);
                if ( cnt!= null ) {
                    cnt.count++;
                }else {
                    map.put(simpleWord, new Obj(1));
                }
            }
        }

        for(String key : map.keySet()) {
            WordCount wd = new WordCount(key,map.get(key).count);
            rs.add(wd);
        }

        Collections.sort(rs, new java.util.ComparatorWordCount(){
            @Override
            public int compare(WordCount o1, WordCount o2) {
                int result = 0 ;
                if (o1.getCount() o2.getCount() ) {
                    result = -1;
                }else if (o1.getCount() o2.getCount()) {
                    result = 1;
                }else {
                    int strRs = o1.getWord().compareToIgnoreCase(o2.getWord());
                    if ( strRs 0 ) {
                        result = 1;
                    }else {
                        result = -1 ;
                    }
                }
                return result;
            }

        });
        return rs;
    }

     
    public static void main(String args[]) {
        String word = "Pinterest is might be aa ab aa ab marketer's dream  - ths site is largely used to curate products " ;
        WordsStatistics s = new WordsStatistics();
        ListWordCount rs = s.statistics(word);
        for(WordCount word1 : rs) {
            System.out.println(word1.getWord()+"*"+word1.getCount());
        }
    }

}