【 tulaoshi.com - Web开发 】
AJAX 客户端页面代码： index.html
代码如下：
html
body
h1Ajax file upload sample/h1br/input id="uplaod" name="btn_send" type="button" value="上传测试"/
div id=result/div
PRE class=js name="code"SCRIPT LANGUAGE=JavaScript
// 上传函数
function btn_send.onclick() {
data = ""
spliter = "-------7d8d733180846"
datadata = data + spliter + "rn"
datadata = data + "Content-Disposition: form-data; name="photofile"; filename="C:a.txt"rn"
// datadata = data + "Content-Type: image/pjpeg" + vbCrLf
datadata = data + "Content-Type: text/plain" + "rn" + "rn"
text = "My name is Wilson Lin."
postLength = text.length + data.length + 2 + spliter.length + 4
package = data + text + "rn" + spliter + "--rn"
alert(package)
// 把XML文档发送到Web服务器
var xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
xmlhttp.open("POST","./upload.php",false);
xmlhttp.setRequestHeader("Content-Type", "multipart/form-data; boundary=-----7d8d733180846");
xmlhttp.setRequestHeader("Content-Length", postLength);
xmlhttp.send(package);
// 显示服务器返回的信息
result.innerHTML=xmlhttp.ResponseText;
}
/SCRIPT
/PRE
/body
/html
PHP服务器端代码： upload.php
代码如下：
?php
// $_FILES['photofile']:是获得上传图片的数组
// $uploadfile：存放地址
$uploadfile = "D:/".$_FILES['photofile']['name'];
copy( $_FILES['photofile']['tmp_name'], $uploadfile );
echo "URL: a href='http://localhost/".$_FILES['photofile']['name']."' target='_blank'".$_FILES['photofile']['name']."/abr/";
?
Upload successed!
